Question

Some velomobile seats have been designed to hold ice packs inside their cushions. If you started a ride with ice packs that held 1100 gg of frozen water at 0 ∘C∘C , and the temperature of the water at the end of the ride was 32 ∘C∘C , how many calories of heat energy were absorbed?

Answer 1

Approximately 34.97 kilocalories of heat energy were absorbed by the water in the velomobile seats.

Step-by-step explanation:

In this scenario, we need to calculate the amount of heat energy absorbed by the water in the velomobile seats. To do this, we can use the formula:

1. q = mcΔT

Where:

• q is the heat energy absorbed
• m is the mass of the water
• c is the specific heat capacity of water, which is 4.18 J/g°C
• ΔT is the change in temperature, which is 32°C - 0°C = 32°C

Let's calculate the heat energy absorbed:

1. q = m * c * ΔT
2. q = 1100 g * 4.18 J/g°C * 32°C
3. q = 146,176 J

Converting this to kilocalories:

1. 1 Joule = 0.000239006 kJ (approximately)
2. q = 146,176 J * 0.000239006 kJ/J
3. q = 34.97 kJ

Therefore, approximately 34.97 kilocalories of heat energy were absorbed by the water in the velomobile seats.