218k views
5 votes
Describe and correct the error(s) made in each of the problems below.

1−x / (5−x)(−x)=x−1 / x(x−5)

5/s+2/5=2/s

User Marjun
by
6.2k points

1 Answer

0 votes

Answer:


\displaystyle (1-x)/((5-x)(-x)) =-(x-1 )/( x(x-5))


\displaystyle (5)/(s)* (2)/(5) =(2)/(s)

Explanation:

Errors in Algebraic Operations

It's usual that students make mistakes when misunderstanding the application of algebra's basic rules. Here we have two of them

  • When we change the signs of all the terms of a polynomial, the expression must be preceded by a negative sign
  • When multiplying negative and positive quantities, if the number of negatives is odd, the result is negative. If the number of negatives is even, the result is positive.
  • Not to confuse product of fractions with the sum of fractions. Rules are quite different

The first expression is


1-x / (5-x)(-x)=x-1 / x(x-5)

Let's arrange into format:


\displaystyle (1-x)/((5-x)(-x)) =(x-1 )/( x(x-5))

We can clearly see in all of the factors in the expression the signs were changed correctly, but the result should have been preceeded with a negative sign, because it makes 3 (odd number) negatives, resulting in a negative expression. The correct form is


\displaystyle (1-x)/((5-x)(-x)) =-(x-1 )/( x(x-5))

Now for the second expression


5/s+2/5=2/s

Let's arrange into format


\displaystyle (5)/(s)+(2)/(5) =(2)/(s)

It's a clear mistake because it was asssumed a product of fractions instead of a SUM of fractions. If the result was correct, then the expression should have been


\displaystyle (5)/(s)* (2)/(5) =(2)/(s)

User Milos K
by
6.3k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.