Answer:
![\displaystyle (1-x)/((5-x)(-x)) =-(x-1 )/( x(x-5))](https://img.qammunity.org/2021/formulas/mathematics/middle-school/9whwprwpa0mh0ydrtq273ot76v3i3b6k53.png)
![\displaystyle (5)/(s)* (2)/(5) =(2)/(s)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/3kwagckvfla2lxtgoz6i2hcdum3ufu0ouj.png)
Explanation:
Errors in Algebraic Operations
It's usual that students make mistakes when misunderstanding the application of algebra's basic rules. Here we have two of them
- When we change the signs of all the terms of a polynomial, the expression must be preceded by a negative sign
- When multiplying negative and positive quantities, if the number of negatives is odd, the result is negative. If the number of negatives is even, the result is positive.
- Not to confuse product of fractions with the sum of fractions. Rules are quite different
The first expression is
![1-x / (5-x)(-x)=x-1 / x(x-5)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/mbsx2gor1u35ae5q0egfl1yn676fcwxnpr.png)
Let's arrange into format:
![\displaystyle (1-x)/((5-x)(-x)) =(x-1 )/( x(x-5))](https://img.qammunity.org/2021/formulas/mathematics/middle-school/n6ldxmwpui0n46iibyyyavvpifa871xi8m.png)
We can clearly see in all of the factors in the expression the signs were changed correctly, but the result should have been preceeded with a negative sign, because it makes 3 (odd number) negatives, resulting in a negative expression. The correct form is
![\displaystyle (1-x)/((5-x)(-x)) =-(x-1 )/( x(x-5))](https://img.qammunity.org/2021/formulas/mathematics/middle-school/9whwprwpa0mh0ydrtq273ot76v3i3b6k53.png)
Now for the second expression
![5/s+2/5=2/s](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ajrwyo83yznh6az7p6rsmgvqru6axwl79b.png)
Let's arrange into format
![\displaystyle (5)/(s)+(2)/(5) =(2)/(s)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/brtzk1mvq3hqkt98hzcxml1ivldr2irb6u.png)
It's a clear mistake because it was asssumed a product of fractions instead of a SUM of fractions. If the result was correct, then the expression should have been
![\displaystyle (5)/(s)* (2)/(5) =(2)/(s)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/3kwagckvfla2lxtgoz6i2hcdum3ufu0ouj.png)