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A box contains 11 two-inch screws, of which 4 have a Phillips head and 7 have a regular head. Suppose that you select 3 screws randomly from the box with replacement. Find the probability there will be more than one Phillips head screw.

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Answer:

The probability that there will be more than one Phillips head screw = 0.1803 .

Explanation:

We are given that there are 11 two-inch screws in a box of which 4 have a Phillips head and 7 have a regular head.

We are selecting 3 screws randomly from the box with replacement, so the probability that there will be more than one Phillips head screw is given by :

  • Probability of selecting two Phillips head screw.
  • Probability of selecting three Phillips head screw.

Now P(selecting 2 Phillips head screw with replacement) is given by :

Selecting 2 Phillip head screw =
(4)/(11) *
(4)/(11) =
(16)/(121)

P(selecting three Phillips head screw) =
(4)/(11) *
(4)/(11) *
(4)/(11) =
(64)/(1331)

Therefore, Probability that there will be more than one Phillips head screw

=
(16)/(121) +
(64)/(1331) =
(240)/(1331) = 0.1803 .

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