Answer:
v_2 = 972 π inch^3
Step-by-step explanation:
Given data:
volume of air V_1 = 288π inc^3
radius of ball at 1 beach = r_1
radius of ball at 2nd beach = r_1 + 3
we know that
![V_1 = 288 \pi](https://img.qammunity.org/2021/formulas/engineering/college/sbln4dovglut90oysm1a5zn0pyz0eomd7u.png)
we know that volume is given as
![v_1 = (4)/(3) \pi r_1^3](https://img.qammunity.org/2021/formulas/engineering/college/b1m84xia06cynxuxigm6h320x8uol0tnya.png)
so equating both side of volume we get
![288\pi = (4)/(3) \pi r_1^3](https://img.qammunity.org/2021/formulas/engineering/college/of22dnsmlfp816magb4dctc6pevpscc7if.png)
r_1 = 6 inch
therefore r_2 = 9 inch
volume of air at 2nd beach
![v_2 = (4)/(3) \pi 9^3](https://img.qammunity.org/2021/formulas/engineering/college/5n82yziprrx0tiuz5i922m0t4czn2stfii.png)
v_2 = 972 π inch^3