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How many moles of chromium (lll) nitrate are produced when chromium reacts with 0.85 moles of lead (IV) Nitrate to produce chromium (lll) nitrate and lead?

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3 votes

Answer:

1.133 moles of chromium (lll) nitrate are produced.

Step-by-step explanation:


4Cr+3Pb(NO_3)_4\rightarrow 4Cr(NO_3)_3+3Pb

Moles of lead(IV) nitrate = 0.85 mole

According to recation, 3 moles of lead(IV) nitrate gives 4 moles of chromium (III) nitrate.

Then 0.85 moles of lead(IV) nitrate will give:


(4)/(3)* 0.85 mol=1.133 mol of chromium (lll) nitrate.

1.133 moles of chromium (lll) nitrate are produced.

User Tom Bevelander
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