Question

How many moles of chromium (lll) nitrate are produced when chromium reacts with 0.85 moles of lead (IV) Nitrate to produce chromium (lll) nitrate and lead?

Answer 1

1.133 moles of chromium (lll) nitrate are produced.

Step-by-step explanation:

`4Cr+3Pb(NO_3)_4\rightarrow 4Cr(NO_3)_3+3Pb`

Moles of lead(IV) nitrate = 0.85 mole

According to recation, 3 moles of lead(IV) nitrate gives 4 moles of chromium (III) nitrate.

Then 0.85 moles of lead(IV) nitrate will give:

`(4)/(3)* 0.85 mol=1.133 mol` of chromium (lll) nitrate.

1.133 moles of chromium (lll) nitrate are produced.