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Which equation has the solutions x = StartFraction 5 plus-or-minus 2 StartRoot 7 EndRoot Over 3 EndFraction?

3x2 – 5x + 7 = 0
3x2 – 5x – 1 = 0
3x2 – 10x + 6 = 0
3x2 – 10x – 1 = 0

2 Answers

5 votes

Answer:

3x^2 - 10x - 1 = 0 $OPTION D ON EDGE$

Explanation:

User Artem M
by
8.6k points
7 votes

Answer:

3x2 – 10x + 6 = 0

Explanation:

Givena general quadratic equation

ax²+bx+c = 0

The general formula for finding x is;

x = -b±√b²-4ac/2a

Where a,b and c are the coefficient of x², x and x° respectively

Given the solution in question to be;

x = 5±2√7/3

The quadratic equation that has thw above general solution will be;

3x²-10x+6 = 0

From the equation, a = 3, b= -10 and c = 6

Substituting this value in the general formula to get x we have;

x = -(-10)±√(-10)²-4(3)(6)/2(3)

x = 10±√100-72/6

x = 10±√28/6

x = 10±√7×4/6

x = 10±2√7/6

Dividing through by 2 gave;

x = 2(5±2√7)/6

x = 5±2√7/3 (which gives the solution in question)

User JonB
by
8.0k points
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