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If 1.80×10^{20} electrons move through a pocket calculator during a full day's operation, how many coulombs of charge moved through it? (answer in C)

User Ganbustein
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1 Answer

4 votes

Answer:

28.836 C

Step-by-step explanation:

Data provided in the question:

Total number of electrons passed through the pocket calculator during a full day's operation = 1.80 × 10²⁰

Now,

We know that the charge of an electron is 1.602 × 10⁻¹⁹ C

Therefore,

The total charge moved through the calculator during the operations

= Total number of electrons passed × Charge of an electron

= (1.80 × 10²⁰) × ( 1.602 × 10⁻¹⁹ )

= 28.836 C

User Ishita Shah
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