Question

An open tank in a petroleum company lab contains a layer of oil on top of a layer of water. The water height is 5 times the oil height h. The oil has a specific gravity of 0.79. If the gage pressure at the bottom of the tank indicates 26.9 mm of mercury, determine the oil height h.

Answer 1

Step-by-step explanation:

Given

specific gravity of oil=0.79

height of oil column is h

height of water column is 5h

Gauge pressure at bottom is equivalent to
`26.9\ mm`

`P_(gauge)=\rho_(Hg) gh_(Hg)`

`P_(gauge)=13.6* 10^3* 9.8* 26.9* 10^(-3)\ Pa`

Pressure due to oil and water at bottom

`P=\rho _(oil)hg+\rho _(w)5hg`

`P=0.79\rho _whg+5\rho _whg=5.79\rho _(w)hg`

`P_(gauge)=P`

`13.6* 10^3* 9.8* 26.9* 10^(-3)=5.79* 10^3* 9.8* h`

`h=63.18\ mm`