Question

What is the period of y = sin(3x)?

StartFraction pi Over 3 EndFraction
StartFraction 2 pi Over 3 EndFraction
3 pi
6 pi

Answer 1

It's B

Explanation:

Chief.

Answer 2

Second option:
`(2\pi )/(3)`

Explanation:

In Trigonometry there are six functions. These functions are:

1) Sine (sin).

2) Cosine (cos).

3) Tangent (tan).

4) Secant (sec).

5) Cosecant (csc).

6) Cotangent (cot).

For this exercise it is important to know that, given a Sine function in the following form:

`ASin(Bx)`

"A" is the Amplitude and the Period of the function is:

`(2\pi )/(|B|)`

In this case you have the following Sine function given in the exercise:

`y = sin(3x)`

So, you can identify that:

`A=1\\\\B=3`

Therefore, in order to find the Period of the funtion given, you need to substitute the value of "B" into
`(2\pi )/(|B|)`.

Then, you get:

`(2\pi )/(|3|)=(2\pi )/(3)`

As you can notice, the Period obtained matches with the one given in the Second option.