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NEED HELP!

What is the zero of the function?
f (x) = x2+x-42/x2+3x-28
Enter your answer in the box.

NEED HELP! What is the zero of the function? f (x) = x2+x-42/x2+3x-28 Enter your answer-example-1

2 Answers

3 votes
x


6.3630657
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1.38899554
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4.75206125
User Giorgos Sfikas
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5 votes


f(x)=\cfrac{x^2+x-42}{x^2+3x-28}\implies \stackrel{f(x)}{0}=\cfrac{x^2+x-42}{x^2+3x-28}\implies 0 = x^2+x-42 \\\\\\ 0=(x+7)(x-6)\implies x= \begin{cases} 6\\ -7 \end{cases}

User Dagelf
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