Question

- What is the equation of a cirde with a center

located at (4, -1) and a radius of 9?

A (x + 4+ (x-1)2 = 9
B. (x + 4) + (-1) = 81
C (x-4) + (+ 1=9
D. (7-4) + ( + 1} = 81

Answer 1

( C ) (x-4)+(+1=9 there is

Answer 2

C.

Explanation:

The equationof a circle:

`(x-h)^2+(y-k)^2=r^2`

(h, k) - center

r - radius

We have center = (4, -1) → h = 4, k = -1, and r = 9.

Substitute:

`(x-4)^2+(y-(-1))^2=9^2\\\\\huge\boxed{(x-4)^2+(y+1)^2=81}`