Answer:
![tan(V)=2.92](https://img.qammunity.org/2021/formulas/mathematics/high-school/jkfavt3siyc5hpx8rj2dhj9fud4lla3b3i.png)
Explanation:
For this exercise you need to remember the following Trigonometric Identity:
![tan\alpha =(opposite)/(adjacent)](https://img.qammunity.org/2021/formulas/mathematics/high-school/qnhd6t3jtmva4wyx7c1884sb74b24sl7iq.png)
You can observe in the figure attached that the given triangle UVW is a Right triangle, because it has an angle that measures 90 degrees.
So, you can identify in the figure that:
![\alpha =V\\\\opposite=UW=35\\\\adjacent=VW=12](https://img.qammunity.org/2021/formulas/mathematics/high-school/2eqy19lyot6z5072x5nsplvtxtfd1t9jmz.png)
Knowing these values, you can substitute them into
:
![tan(V)=(35)/(12)](https://img.qammunity.org/2021/formulas/mathematics/high-school/cf5nkqeilhh0dgrn66l3hnbcm08lfsvnox.png)
Now you must evaluate:
![tan(V)=2.916](https://img.qammunity.org/2021/formulas/mathematics/high-school/e8pj5w0akibailhfv1oshrj0woq16q6onq.png)
Finally, rounded it to the nearest hundreth, you get:
![tan(V)=2.92](https://img.qammunity.org/2021/formulas/mathematics/high-school/jkfavt3siyc5hpx8rj2dhj9fud4lla3b3i.png)