Question

Please show steps and show restrictions

Answer 1

`(x^2+7x+12)/(x^2-x-12)\\\\=(x^2 +3x+4x +12)/(x^2 -4x+3x-12)\\\\=(x(x+3)+4(x+3))/(x(x-4)+3(x-4))\\\\=((x+4)(x+3))/((x-4)(x+3))\\\\=(x+4)/(x-4)\\\\\text{Restrictions:}~ x\\eq 4 ,~ x\\eq -3`