Question

A 805 kg test car travels around a 4.25 km circular track. If the magnitude of the force that maintains the car’s circular motion is 3140 N, what is the car’s tangential speed?

Answer 1

rdfdfsdfsdfdfgs

Step-by-step explanation:

Answer 2

v = 51.36 m/s

Step-by-step explanation:

given,

mass of the car = 805 Kg

circumference of the track = 4.25 Km

Force on the car in circular path, F = 3140 N

tangential speed of the car = ?

2 π r = 4250

r = 676.4 m

using formula

`F = (mv^2)/(r)`

`3140 = (805* v^2)/(676.4)`

v² = 2638.38

v = 51.36 m/s

hence, tangential speed of the car is equal to 51.36 m/s