In a population of 1000 snails, tests of snail color genes show that 160 snails are AA, 480 are Aa and 360 are aa. What is the frequency of the A allele in this population? .04 …

Question

asked Nov 4, 2021 41.8k views

1 Answer

Yildirim · Answer 1 · 2021-11-08T15:02:40+0000

Answer:

Option C.

Explanation:

Total population = 1000 snails

AA = 160 snails

Aa = 480 snails

aa = 360 snails

Frequency of each type.

AA=(160)/(1000)=0.16

Aa=(480)/(1000)=0.48

aa=(360)/(1000)=0.36

Now, we get

$A^2=0.16\Rightarrow A=√(0.16)=0.4$

he frequency of the A allele in this population is 0.4.

Therefore, the correct option is C.