Question

Astrology, that unlikely and vague pseudoscience, makes much of the position of the planets at the moment of one's birth. The only known force a planet exerts on Earth is gravitational.Calculate the magnitude of the gravitational force exerted on 4.2 kg baby by a 100 kg father 0.2 m away at birth.

Answer 1

`7.01*10^(-8)`N

Step-by-step explanation:

Gravitational force formula is given by;

`F_(g)=(GMm)/((r)^(2))`

where G = gravitational constant

M and m = masses given

r = distance given in radius

Concerning this question, we can make a substitute of the formula to be:

`F_(father)=(G*M_(father)*m_(baby))/((r)^(2))`

Where; G = gravitational constant ⇒
`6.673*10^(-11)(Nm^2)/(kg^2)`

M = mass of the father ⇒ 100kg

m = mass of the child ⇒ 4.2kg

r = distance between father and child ⇒ 0.2m

`F_(father)` =
`(6.673*10^(-11)(Nm^2)/(kg^2) *100kg*4.2kg)/((0.2m)^2)`

=
`7.01*10^(-8)`N

∴ We can now conclude that the gravitational force exerted on the baby by the father at birth is
`7.01*10^(-8)`N