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An electron initially at rest accelerates through a potential difference of 1 V, gaining kinetic energy KEe, whereas a proton, also initially at rest, accelerates through a potential difference of - 1 V, gaining kinetic energy KEp. Which of the following relationships holds?

a) Cannot be determined from the given information.
b) KEe > KEp
c) KEe < KEp
d) KEe = KEp

User Jeff Maes
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1 Answer

3 votes

Answer:

d) KEe = KEp

Step-by-step explanation:

According to the law of conservation of energy, the electric potential energy is converted into the kinetic energy of the particle:


KE=U\\KE=qV

Here, q is the particle's charge and V is the potential difference.

The charge of the electron is -e. So:


KE_e=-eV\\KE_e=-e(1V)

The charge of the proton is e. So:


KE_p=eV\\KE_p=e(-1V)\\KE_p=-e(1V)

So
KE_e=KE_p

User Bibek Shakya
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