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What is the equation of the line that passes through the point (6.14) and is parallel to the line with the following equation?

y = -x - 1
OA. y = -x + 6
B.
y =
-x + 22
C.
v
=
+ 20
OD.y =

User Mod
by
5.1k points

1 Answer

2 votes

Therefore the equation of the required line is
x+y= 20

Explanation:

Given,

a line passes through the point (6,14) and is parallel to the line y =-x-1.

The slope of the given line is -1. [ the coefficient of x]

Since the required line parallel to the given line.

So, the slope of required line is = -1

The equation of line which passes through the point
(x_1,y_1) and slope is m is
y-y_1=m(x-x_1)

Therefore the equation of the required line is


y - 14= -1(x-6)


\Leftrightarrow y -14 = -x+6


\Leftrightarrow x+y= 20

User RunHolt
by
5.2k points
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