Question

What is the equation of the line that passes through the point (6.14) and is parallel to the line with the following equation?

y = -x - 1
OA. y = -x + 6
B.
y =
-x + 22
C.
v
=
+ 20
OD.y =

Answer 1

Therefore the equation of the required line is
`x+y= 20`

Explanation:

Given,

a line passes through the point (6,14) and is parallel to the line y =-x-1.

The slope of the given line is -1. [ the coefficient of x]

Since the required line parallel to the given line.

So, the slope of required line is = -1

The equation of line which passes through the point
`(x_1,y_1)` and slope is m is
`y-y_1=m(x-x_1)`

Therefore the equation of the required line is

`y - 14= -1(x-6)`

`\Leftrightarrow y -14 = -x+6`

`\Leftrightarrow x+y= 20`