1 Answer

Amitshree · Answer 1 · 2023-06-22T06:46:38+0000

Answer:

$\sf x < (16)/(7) ,x > (16)/(7)$

Explanation:

Given function:

$\sf f[g(x)]=(-6+23)/(7x-16)$

The domain will be values of x that do NOT make the denominator zero:

$\sf \implies 7x-16=0$

$\sf \implies 7x=16$

$\sf \implies x=(16)/(7)$

Therefore, the domain is
$\sf x\\eq (16)/(7)$ so

$\sf x < (16)/(7) ,x > (16)/(7)$

Please log in or register to add a comment.