Answer:
Upright, Reduced
Step-by-step explanation:
Given that,
Height of the object, h = 20 cm
Image distance, v = 25 cm
Height of the image, h' = 5 cm
We know that the magnification of the mirror is given by :
![m=(h')/(h)=(v)/(u)](https://img.qammunity.org/2021/formulas/physics/college/xyla9rc7y77oenif1nhtwll5xhmhdn3a2d.png)
![(5)/(20)=(25)/(u)](https://img.qammunity.org/2021/formulas/physics/college/lkfbzvaooext37qps22bsjfreib0uwhskb.png)
u = -100 cm (negative due to sign conventions)
Let f is the focal length of the lens. It can be calculated as :
![(1)/(f)=(1)/(v)-(1)/(u)](https://img.qammunity.org/2021/formulas/physics/college/glyfeeltoezc2pfvj40sfh4amagib2tk34.png)
![(1)/(f)=(1)/(25)-(1)/((-100))](https://img.qammunity.org/2021/formulas/physics/college/gxojxm14u8x5kkfsf4y8ffkmg9znwa8nja.png)
f = 20 cm
It is seen that the focal length of the lens is positive. So, it is a convex lens. The image formed by the convex lens is Upright, Reduced. Hence, the correct option is (a).