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Two submarines are underwater and approaching each other head-on.Sub A has a speed of 4 m/s and sub B has aspeed of 14 m/s. Sub A sends out a1910 Hz sonar wave that travels at a speedof 1522 m/s.(a) What is the frequency of the sound detected by subB (to the nearest Hz)?Hz(b) Part of the sonar wave is reflected from B and returns to A.What frequency does A detect for this reflected wave (to thenearest Hz)?Hz

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Answer:

1933 Hz

1956 Hz

Step-by-step explanation:


v_0 = Velocity of object


v_s = Velocity of source

v = Velocity of sound

From Doppler effect


f=f'(v+v_0)/(v-v_s)\\\Rightarrow f=1910(1522+14)/(1522-4)\\\Rightarrow f=1932.64822134\ Hz=1933\ Hz

The frequency of the sound detected by subB is 1933 Hz


f=f'(v+v_0)/(v-v_s)\\\Rightarrow f=1932.64822134(1522+4)/(1522-14)\\\Rightarrow f=1955.7169\ Hz=1956\ Hz

The frequency of the sound detected by subA is 1956 Hz

User Michael Levy
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