Answer:
Explanation:
Given that a heterozygous white-fruited squash plant is crossed with a yellow-fruited plant, yielding 200 seeds. Of these, 110 produce white-fruited plants while only 90 produce yellow-fruited plants
We set up hypotheses as
H0: Both produce equal seeds
Ha: Both produce different number of seeds
(Two tailed chi square test at 5% level of significance)
If null hypothesis were true, expected would be
100 each
Chi square = Sum of (observed-expected)^2/expected
=
![(110-100)^2/100 + (90-100)^2/100\\= 20](https://img.qammunity.org/2021/formulas/mathematics/high-school/7yk32b3wck61vubr38k51h5dinnt5iaphz.png)
df = 1
p value <0.00001
Since p is less than 0.05 we reject null hypothesis
There is significant difference between the number of plants produced.