Answer:
![9.4\ miles](https://img.qammunity.org/2021/formulas/mathematics/middle-school/hcprxgekywxsqkn614xpkbi0h8h7xz7vfg.png)
Explanation:
You can draw a Right triangle, as the one shown in the picture attached, where "x" is the distance between Troy and his starting point.
You need to use the Pythagorean Theorem. This is:
![a^2=b^2+c^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/6avf83462ea4wtacy27l1yqnjigwj9z5bp.png)
Where "a" is the hypotenuse, and "b" and "c" are the legs of the Right triangle.
In this case, you can identify that the legs of the Right triangle are:
![a=x\\\\b=8\ mi\\\\c=5\ mi](https://img.qammunity.org/2021/formulas/mathematics/middle-school/sijttpn2lt9pvir7h3q2gagra37lj72owq.png)
Therefore, you can substitute values into
:
![x^2=(8\ mi)^2+(5\ mi)^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/7r2b1el0acdqpxty8q8jvhivpc1dqedbzq.png)
Now you need to solve for "x" in order to find its value. This is:
![x=√((8\ mi)^2+(5\ mi)^2)\\\\x=9.43\ mi](https://img.qammunity.org/2021/formulas/mathematics/middle-school/9il5zhuujmf57abaff6r3ouaiw72k91llr.png)
Finally, rounding the result to the nearest tenth of a mile, you get:
![x\approx9.4\ mi](https://img.qammunity.org/2021/formulas/mathematics/middle-school/vylwyzn8gvma8s0z5l5457qvd05ww6h0d4.png)