Question

A child is building a tower with colored bricks. She has 21 bricks: 5 yellow, 4 blue, 2 green, and 10 red. She selects a brick at random to stack on the tower. Enter all answers as decimals and round to four places.

Answer 1

The probability of picking a Yellow, Blue, green and red brick respectively is 0.2381, 0.1905, 0.0952 and 0.4762.

Explanation:

If all bricks have an equal chance to get picked, the probability can be calculated as:

`P(b=x)=\displaystyle(n\ºx_(brick))/(n\ºtotalcases)`

The number of total bricks is 21. Therefoere the probability of picking a Yellow, Blue, green and red brick respectively is:

`P(b=Y)=\displaystyle(n\ºx_y)/(n\ºtotalcases)=(5)/(21)=0.2381`

`P(b=bl)=\displaystyle(n\ºx_(bl))/(n\ºtotalcases)=(4)/(21)=0.1905`

`P(b=g)=\displaystyle(n\ºx_g)/(n\ºtotalcases)=(2)/(21)=0.0952`

`P(b=R)=\displaystyle(n\ºx_R)/(n\ºtotalcases)=(10)/(21)=0.4762`