Answer:
B. 53 square inches
Explanation:
The attached figure is drawn to scale, and a grid is provided that makes it easier to see the dimensions of the various parts.
This figure can be easily decomposed into an overall rectangle with cutouts of a trapezoid at the top and a rectangle at the bottom right.
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The overall rectangle has dimensions 8 units wide and 10 units high.
The trapezoid at the top has bases of 8 units and 7 units, and a height of 2 units.
The rectangle at the bottom right has dimensions of 4 units wide and 3 units high.
The area formulas for a rectangle and trapezoid are ...
A = LW . . . . area of a rectangle with length L, width W
A = 1/2(b1 +b2)h . . . . area of a trapezoid with bases b1, b2, and height h
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Then the area of the figure is ...
figure area = overall rectangle - trapezoid - lower right rectangle
= (8 in)(10 in) - 1/2(7 in + 8 in)(2 in) -(4 in)(3 in)
= 80 in² -15 in² -12 in² = 53 in²
The area of the object is 53 square inches.