Question

After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 55.0 cm. She finds the pendulum makes 100 complete swings in a time of 145s.what is the value of g on this planet?g= ______ m/s^2?

Answer 1

Acceleration due to gravity will be
`g=5.718m/sec^2`

Step-by-step explanation:

We have given length of pendulum l = 55 cm = 0.55 m

It is given that pendulum completed 100 swings in 145 sec

So time taken by pendulum for 1 swing
`=(145)/(100)=1.45sec`

We have to find the acceleration due to gravity at that point

We know that time period of pendulum;um is given by

`T=2\pi \sqrt{(l)/(g)}`

So
`1.45=2* 3.14* \sqrt{(0.55)/(g)}`

`\sqrt{(0.55)/(g)}=0.230`

Squaring both side

`{(0.3025)/(g)}=0.0529`

`g=5.718m/sec^2`

So acceleration due to gravity will be
`g=5.718m/sec^2`