Question

A -5.0 μC charge experiences a 11 i^ N electric force in a certain electric field. [Recall that i^ is a unit vector in the x-direction.]

1. What force would a proton experience in the same field?

Answer 1

The force experienced by a proton in the same electric field is 1.76x10^-18 i^ N.

Step-by-step explanation:

The force experienced by a particle in an electric field is given by the equation:

F = qE

Where F is the force, q is the charge of the particle, and E is the electric field strength. In this case, a proton has a charge of +1.6x10^-19 C. Given that the force on the -5.0 μC charge is 11 i^ N, we can find the force on the proton by substituting the values into the equation:

F = (1.6x10^-19 C)(11 i^ N) = 1.76x10^-18 i^ N

Therefore, the force experienced by a proton in the same electric field is 1.76x10^-18 i^ N.

Answer 2

`\vec{F}= -3.52* 10^(-13)\hat{i}\ N`

Step-by-step explanation:

given,

charge = -5.0 μC

Electric force, F = 11 i^ N

force would a proton experience = ?

we know

`\vec{F} = q \vec{E}`

`11\hat{i} = -5 * 10^(-6) \vec{E}`

`\vec{E} =-2.2 * 10^(6)\hat{i}`

we know charge of proton is equal to 1.6 x 10⁻¹⁹ C

using formula

`\vec{F} = q \vec{E}`

`\vec{F}= 1.6 * 10^(-19)* -2.2 * 10^(6)\hat{i}`

`\vec{F}= -3.52* 10^(-13)\hat{i}\ N`

Force experienced by the photon in the same field is equal to
`\vec{F}= -3.52* 10^(-13)\hat{i}\ N`