Complete question:
A 7.0 -μC point charge and a 9.0 -μC point charge are initially infinitely far apart. How much work does it take to bring the 7.0-μC point charge to x=3.0 mm, y= 0.0mm and the 9.0-μC point charge to x=-3.0 mm, y=0.0 mm? (the value of k is 9.0*10^9 N*m^2/C^2)
Answer:
- Work done in bringing 7.0-μC point charge from infinity to x=3.0 mm, y= 0.0mm is 21 x 10⁶ Volts
- work done in bringing 9.0-μC point charge from infinity to x=-3.0 mm, y=0.0 mm is -27 x 10⁶ Volts.
Step-by-step explanation:
Work done in bringing a unit positive charge from infinity to that point in electric filed (V) = Electric field strength X distance
where;
K is a constant = 9X10⁹ N.m²/C²
q is point charge in C
d is the distance in m
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Work done in bringing 7.0-μC point charge from infinity to x=3.0 mm, y= 0.0mm
V = 21 x 10⁶ Volts
Work done in bringing 9.0-μC point charge from infinity to x=-3.0 mm, y=0.0 mm
V = -27 x 10⁶ Volts
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Work done in bringing 7.0-μC point charge from infinity to x=3.0 mm, y= 0.0mm is 21 x 10⁶ Volts While work done in bringing 9.0-μC point charge from infinity to x=-3.0 mm, y=0.0 mm is -27 x 10⁶ Volts.