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1.42 mol sample of neon gas at a temperature of 13.0 °C is found to occupy a volume of 25.5 liters. The pressure of this gas sample is mm Hg. ?

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Answer: 996 mmHg

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at NTP, weighs equal to the molecular mass and contains avogadro's number
6.023* 10^(23) of particles.

According to the ideal gas equation:


PV=nRT

P = Pressure of the gas = ?

V= Volume of the gas = 25.5 L

T= Temperature of the gas = 13°C = (273+13) K = 286K

R= Gas constant = 0.0821 atmL/K mol

n= moles of gas= 1.42


P=(nRT)/(V)=(1.42* 0.0821* 286)/(25.5)=1.31atm=996mmHg (760mmHg=1atm)

Thus pressure of this gas sample is 996 mm Hg.

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