Question

You measure out 14.66 mL of vinegar solution. You used 13.58 mL of 0.115 M NaOH solution to titrations to the endpoint. What what the lol story of the vinegar solution?

Answer 1

Molarity of Vinegar solution is 0.107 M

Step-by-step explanation:

Let V1 be the volume of NaOH = 13.58 ml

Let V2 be the volume of Vinegar = 14.66 ml

Let M1 be the molarity of NaOH = 0.115 M

Let M2 be the molarity of Vinegar = ?

Using the Law of Volumetric analysis, V1M1= V2M2

Rearranging the equation to get M2 as,

M2 = V1M1/V2 = 13.58 ml * 0.115 M/14.66 ml = 0.107 M

So the Molarity of Vinegar = 0.107 M