Question

Consider as a system the gas in a vertical cylinder; the cylinder is fitted with a piston onwhich a number of small weights are placed. The initial pressure is 200 kPa, and the initial volume ofthe gas is 0.04 m^3. Let a bunsen burner be placed under the cylinder, and let thevolume of the gas increase 0.1m^3 while the pressure remainsconstant.

A. Calculate the work done by the system during this process.

Answer 1

Work done = 12,000J = 12KJ

Step-by-step explanation:

This process is an Isobaric one i.e a process at constant pressure

• P = 200KPa = 200 x 1000 Pa = 200,000Pa

• Vi = 0.04m3

• Vf = 0.1m3

From the formula for Workdone = Integral (PdV)

Work done = P ( Vf - Vi)

Plugging the values in the equation,

Work done = 200,000 ( 0.1 - 0.04)

Work done = 12,000J = 12KJ