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A test charge of 0.002 C experiences a force of 0.50 N on it is placed in an electric field. Find the intensity of the electric field
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A test charge of 0.002 C experiences a force of 0.50 N on it is placed in an electric field. Find the intensity of the electric field

User ConnorWGarvey
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1 Answer

1 vote

Answer:

250 N/C

Step-by-step explanation:

E=F/q=0,5N/0,002C=250N/C

User John Myles White
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