Answer:
No,
and
are not inverses of each other.
Explanation:
Given functions:


To tell whether
and
are inverse of each other.
Solution:
If
and
are inverse of each other, then:
or

Thus, to check if they are inverse of each other, we will find inverse of function
and see if it is =

We have:

In order to find inverse we will replace
with


Then we switch
and


Then, we solve for

Subtracting both sides by 4.


Multiplying both sides by 2.

Using distribution:

Dividing both sides by -3.


Thus inverse of function
can be given as:

Since
, hence they are not inverse functions of each other.