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If tan=4/3 in quardrant 1 find cos and sin

2 Answers

1 vote


\displaystyle\bf\\If~tan\,\theta=(4)/(3)~~then\\\\sin\,\theta=(4)/(√(4^2+3^2))=(4)/(√(16+9))=(4)/(√(25))=(4)/(5)\\\\\boxed{\bf~sin\,\theta=(4)/(5)}\\\\\\cos\,\theta=(3)/(√(4^2+3^2))=(3)/(√(16+9))=(3)/(√(25))=(3)/(5)\\\\\boxed{\bf~cos\,\theta=(3)/(5)}

User Shahidul
by
8.5k points
4 votes

Answer:

cos = 3/5

sin = 4/5

Explanation:

tan=4/3 Q1

if you use Pythagorean theorem


c {}^(2) = a {}^(2) + b {}^(2) \\ c {}^(2) = 4 {}^(2) + 3 {}^(2) \\ c {}^(2) = 16 + 9 \\ c {}^(2) = 25 \\ c = + - 5 \\

Becauseof Q1

c=5

to picture

sin = 4/5

cos = 3/5

If tan=4/3 in quardrant 1 find cos and sin-example-1
User Irshad Ahmad
by
8.7k points

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