Question

If tan=4/3 in quardrant 1 find cos and sin

Answer 1

`\displaystyle\bf\\If~tan\,\theta=(4)/(3)~~then\\\\sin\,\theta=(4)/(√(4^2+3^2))=(4)/(√(16+9))=(4)/(√(25))=(4)/(5)\\\\\boxed{\bf~sin\,\theta=(4)/(5)}\\\\\\cos\,\theta=(3)/(√(4^2+3^2))=(3)/(√(16+9))=(3)/(√(25))=(3)/(5)\\\\\boxed{\bf~cos\,\theta=(3)/(5)}`

Answer 2

cos = 3/5

sin = 4/5

Explanation:

tan=4/3 Q1

if you use Pythagorean theorem

`c {}^(2) = a {}^(2) + b {}^(2) \\ c {}^(2) = 4 {}^(2) + 3 {}^(2) \\ c {}^(2) = 16 + 9 \\ c {}^(2) = 25 \\ c = + - 5 \\`

Becauseof Q1

c=5

to picture

sin = 4/5

cos = 3/5