Question

What is the solution to this system of linear equations?

2x + y = 1

3x – y = –6

(–1, 3)
(1, –1)
(2, 3)
(5, 0)
Mark this and return

Answer 1

Answer: (–1, 3)

Explanation:

The given system of linear simultaneous equations is expressed as

2x + y = 1 - - - - - - - - - - -1

3x – y = –6 - - - - - - - - - -2

We would eliminate y by adding equation 1 to equation 2. It becomes

2x + 3x = 1 - 6

5x = - 5

Dividing the left hand side and the right hand side of the equation by 5, it becomes

5x/5 = - 5/5

x = - 1

Substituting x = - 1 into equation 1, it becomes

2 × - 1 + y = 1

- 2 + y = 1

Adding 2 to the left hand side and the right hand side of the equation, it becomes

- 2 + 2 + y = 1 + 2

y = 3

Answer 2

In this question, you're solving the systems of equations.

Solve:

2x + y = 1

3x - y = -6

Since the y's could cancel out, lets solve for x

2x + y = 1

3x - y = -6

-------------------

5x = -5

x = -1

Now, we know that x = -1, lets find y by plugging in -1 to x in any of the equations.

2(-1) + y = 1

-2 + y = 1

Add 2 to both sides

y = 3

This means that your answer would be (-1, 3)

Answer:

(-1, 3)