Question

2 A pharmacist has a 13 % alcohol solution and another 18 % alcohol solution. How much of each must he use to make 50 grams of a 14 % alcohol solution

Answer 1

40 of first and 10 of second

Explanation:

Answer 2

Therefore he took 40 gram of
`1^(st)` type solution and 10 gram of
`2^(nd)` type solution.

Explanation:

Given that , A pharmacist 13% alcohol solution another 18% alcohol solution .

Let he took x gram solution of
`1^(st)` type solution

and he took (50-x) gram of
`2^(nd)` type solution.

Total amount of alcohol =
`[x*(13)/(100)] +[(50 -x) *(18)/(100) ]` gram

Total amount of solution = 50 gram

According to problem

⇔
`( [x*(13)/(100)] +[(50 -x) *(18)/(100) ])/(50)= (14)/(100)`

⇔
`(13x +900-18x)/(100*50) =(14)/(100)`

⇔- 5x= 700 - 900

⇔5x = 200

⇔x = 40 gram

Therefore he took 40 gram of
`1^(st)` type solution and (50 -40)gram = 10 gram of
`2^(nd)` type solution.