Question

Write an equation of the line parallel to y=3x+2 that passes through (-1, -2)

Answer 1

`y=3x+1`

Explanation:

From the question, we are given;

• The equation y = 3x + 2
• A point (-1, -2)

We are required to determine the equation of a line parallel to the given line and passing through the point (-1, -2)

• We are going to determine the gradient of the line first; when an equation is written in the form of y = mx + c, where m is the gradient.

y = 3x + 2, m₁ = 3

• But, m₁ = m₂ for parallel lines
• Therefore, the gradient of the line in question, m₂ is 3
• With the gradient, m₂=3 , and a point (-1, -2) we can get its equation;

Taking another point (x, y)...

Then;

`(y+2)/(x+1)=3`

`y+2=3(x+1)\\y+2=3x+3\\y=3x+1`

Therefore; the equation of the line is
`y=3x+1`