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Which is the best estimate for (6.3 times 10 Superscript negative 2 Baseline) (9.9 times 10 Superscript negative 3 Baseline) written in scientific notation?

6 times 10 Superscript negative 4
60 times 10 Superscript negative 5
6 times 10 Superscript 7
6 times 10 Superscript 7

2 Answers

1 vote

Answer:

the answer is a

Explanation:

i took the test... 100% i swear

User Aristotll
by
7.9k points
3 votes

Answer:

First option:
6*10^(-4)

Explanation:

The expression is:


(6.3*10^(-2))(9.9*10^(-3))

Scientific Notation (which is also known as "Standard form"), is a way to write numbers. It is very useful to handle very small numbers and very large numbers.

By definition, Scientific Notation has the following form:


a*10^n

Where the coefficient "a" is a number from 1 to 10 without including 10, and the exponent "n" is an Integer.

Given:


(6.3*10^(-2))(9.9*10^(-3))

If you want to estimate the result, you can round the coefficients to the nearest whole number. Since the decimal point must be just after the first digit, you know that:


(6*10^(-2))(10*10^(-3))=(6*10^(-2))(1*10^(-2))

Now you need to remember the Product of powers properties:


(a^m)(a^n)=a^((m+n))

Then, solving the multiplication, you get:


6*10^(-4)

User Flavio Wuensche
by
8.3k points

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