Question

Two capacitors with capacitances of 16 nF and 24 nF, respectively, are connected in parallel. This combination is then connected to a battery. If the charge on the 16 nF capacitor is 56 nC, what is the charge on the 24 nF capacitor

Answer 1

charge on the 24 nF capacitor is 84 nC

Step-by-step explanation:

given data

capacitance Q1 = 16 nF

capacitance Q2 = 24 nF

charge on the 16 nF capacitor C1 = 56 nC

solution

we get here capacitor in parallel have same voltage

V1 = V2 ...............1

here voltage V1 =
`(Q1)/(C1)`

`(Q1)/(C1)` =
`(Q2)/(C2)` .....................2

put here value we get

`(56)/(16) = (Q2)/(24)`

Q = 84 nC

so charge on the 24 nF capacitor is 84 nC