Answer:
The maximum speed of the heart wall during this motion is 0.032 m/s.
Step-by-step explanation:
Given that,
Amplitude of the simple harmonic motion, A = 1.7 mm = 0.0017 m
Frequency of the fetus's ventricular wall, f = 3 Hz
We need to find the maximum speed of the heart wall during this motion. The maximum speed of the object that is executing SHM is given by :
![v_(max)=A\omega](https://img.qammunity.org/2021/formulas/physics/college/r7zmpi3bxhtnqvd2ufbu1eo72iap1au53j.png)
![v_(max)=2\pi f A](https://img.qammunity.org/2021/formulas/physics/high-school/l365whi2k07trwtxbpd5vu31amp644lnb1.png)
![v_(max)=2\pi * 3* 0.0017](https://img.qammunity.org/2021/formulas/physics/high-school/fp7nid3fuypctuzw47l5a2sdy68gryk8uk.png)
![v_(max)=0.032\ m/s](https://img.qammunity.org/2021/formulas/physics/high-school/qa7ld9nuqsy2gwwcf98731qsd09grb444c.png)
So, the maximum speed of the heart wall during this motion is 0.032 m/s. Hence, this is the required solution.