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Suppose the fetus's ventricular wall moves back and forth in a pattern approximating simple harmonic motion with an amplitude of 1.7 mm and a frequency of 3.0 Hz. Find the maximum speed of the heart wall (in m/s) during this motion. Be careful of units!

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Answer:

The maximum speed of the heart wall during this motion is 0.032 m/s.

Step-by-step explanation:

Given that,

Amplitude of the simple harmonic motion, A = 1.7 mm = 0.0017 m

Frequency of the fetus's ventricular wall, f = 3 Hz

We need to find the maximum speed of the heart wall during this motion. The maximum speed of the object that is executing SHM is given by :


v_(max)=A\omega


v_(max)=2\pi f A


v_(max)=2\pi * 3* 0.0017


v_(max)=0.032\ m/s

So, the maximum speed of the heart wall during this motion is 0.032 m/s. Hence, this is the required solution.

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