Question

The displacement of an oscillating mass is 0.004*sin(7t) meters. What is the peak amplitude of its velocity in meters/second?

Answer 1

The peak amplitude velocity is found to be 0.028 m/s.

Step-by-step explanation:

Given that the displacement of an oscillating mass is:

Displacement = x = 0.004 Sin(7t)

Now, to find out the velocity of this particle, me have to take derivative of 'x' with respect to 't'.

Velocity = V = dx/dt = (7)(0.004)Cos (7t)

V = 0.028 Cos (7t)

Now, for the maximum displacement, the value of the Cos function must be maximum. And we know that the maximum value of Cos function is 1. Thus, to get maximum displacement, we set the value of Cos (7t) to be equal to 1.

Vmax = 0.028(1)

Vmax = 0.028 m/s (Peak Amplitude of Velocity)