Question

For a given sand soil, the maximum and minimum void ratios are 0.78 and 0.43, respectively.

Given that Gs = 2.67, determine the dry unit weight of the soil when the relative density is 65% (in lb/ft^3).

Answer 1

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Step-by-step explanation:

a.) Dry unit weight b.) Void ratio c.) Porosity d.) Degree of saturation Solution: a) γd= γ1+?= 17.611.108= 15.89 kN/m3b) γd= γ? ?1+15.89 = (2.67)(9.81)1+e = 0.65 c) n = e1+= 0.651.65= 0.39 d) Se = wGsS = (0.108)(2.67)0.65x 100% = 44.50% 3.2Refer to Problem 3.1. Determine the weight of water, in KN, to be added per cubic meter of soil for: a.) 80% DEGREE OF SATURATION b.) 100% DEGREE OF SATURATION Solution: a. ) S = v? ??∆S = 80 –44.50 = 35.5% n = v? ?; VT = 1m3 0.39 = v? 1Vv = 0.39 0.355 = v? 0.39; Vw = (0.355)(0.39) Vw = 0.140 m3 Ww = 0.140 x 9.81 = 1.37 Kn