Question

A current is flowing to point A from the power supply and a current out of point A through each of the two resistive branches. What is the relationship between these three currents?

Answer 1

`I_(in)=I_1+I_2`

Step-by-step explanation:

This can be explained by Kirchhoff's Law which is in sync with the conservation of energy stating that the total current incoming at the junction is always equal to the total current outgoing from it.

So,

`I_(in)=I_1+I_2`

`I_(in)=(V_1)/(R_1) +(V_2)/(R_2)`

A higher current will flow through the lesser resistant conductor and vice-versa because the current has a tendency to follow the path of least resistance.