Question

Gaseous compound Q contains only xenon and oxygen. When a 0.100 g sample of Q is placed in a 50.0-mL steel vessel at 0 C, the pressure is 0.230 atm. What is the likely formula of the compound?

Answer 1

The question is incomplete, here is the complete question:

Gaseous compound Q contains only xenon and oxygen. When a 0.100 g sample of Q is placed in a 50.0-mL steel vessel at 0°C, the pressure is 0.230 atm. What is the likely formula of the compound?

A. XeO

B.
`XeO_4`

C.
`Xe_2O_2`

D.
`Xe_2O_3`

E.
`Xe_3O_2`

Answer: The chemical formula of the compound is
`XeO_4`

Step-by-step explanation:

To calculate the molecular weight of the compound, we use the equation given by ideal gas equation:

PV = nRT

Or,

`PV=(w)/(M)RT`

where,

P = Pressure of the gas = 0.230 atm

V = Volume of the gas = 50.0 mL = 0.050 L (Conversion factor: 1 L = 1000 mL)

w = Weight of the gas = 0.100 g

M = Molar mass of gas = ?

R = Gas constant =
`0.0821\text{ L atm }mol^(-1)K^(-1)`

T = Temperature of the gas =
`0^oC=273K`

Putting value in above equation, we get:

`0.230* 0.050=(0.100)/(M)* 0.0821* 273\\\\M=(0.100* 0.0821* 273)/(0.230* 0.050)=194.9g/mol\approx 195g/mol`

The compound having mass as calculated is
`XeO_4`

Hence, the chemical formula of the compound is
`XeO_4`