Answer:
The flea will move high to a height of 0.05 meters.
Step-by-step explanation:
Given that,
Acceleration of the flea,
![a=1000\ m/s^2](https://img.qammunity.org/2021/formulas/physics/college/iuk9xtzrs4ezoc3g69jxfrgj5oxck2du3o.png)
Distance, d = 0.5 mm = 0.0005 m
Let u and v are the initial and final velocity of the flea. Using equation of motion as :
![v^2-u^2=2ad](https://img.qammunity.org/2021/formulas/physics/college/8xb8qdvmwzu19o1iuift32eskxnwzfhjvy.png)
![v^2-u^2=2* 1000* 0.0005](https://img.qammunity.org/2021/formulas/physics/college/tu7fav7tbnjtkqdtwony5107da25xti53k.png)
..........(1)
Using conservation of energy, we get :
![(1)/(2)mu^2=(1)/(2)mv^2+mgh](https://img.qammunity.org/2021/formulas/physics/college/sdzi6yov8n5xresmigi37c3e90p3sbqzje.png)
![(1)/(2)u^2=(1)/(2)v^2+(-g)h](https://img.qammunity.org/2021/formulas/physics/college/ar9vnf2tfovjqzsl93s4b0cf8b9zt5trsm.png)
![(1)/(2)u^2=(1)/(2)v^2-gh](https://img.qammunity.org/2021/formulas/physics/college/1d422u28v6dvrk8exlnvz3kld1pu0b4w2w.png)
![(1)/(2g)(u^2-v^2)=-h](https://img.qammunity.org/2021/formulas/physics/college/o357gt1havhqrdi0dbawrjkabczhpx1ary.png)
![h=(1)/(2* 9.8)](https://img.qammunity.org/2021/formulas/physics/college/lnn0owa25sx84hpcckmapq086jgcuiajbf.png)
h = 0.05 meters
So, the flea will move high to a height of 0.05 meters. Hence, this is the required solution.