Question

A soil specimen was tested to have a moisture content of 32%, a void ratio of 0.95, and a specific gravity of soil solids of 2.75. Determine:

a. the degree of satruation
b. porosity
c. dry unit weight

Answer 1

a. 0.9263

b. 0.4872

c. 13.83kN/m
`^(3)`

Step-by-step explanation:

moisture content (ω) = 0.32

void ratio (e) = 0.95

specific gravity (
`G_(s)`) = 2.75

the degree of satruation (S) =
`(w . G_(s) )/(e)` =0.32×2.75/0.95 = 0.9263

b. porosity (n) =
`(e)/(e + 1)` = 0.95/(0.95 + 1)= 0.4872

c. dry unit weight (γ
`_(d)`) =
`(G_(s) . V_(w) )/(1 + e)`

taking specific unit weight of water (V
`_(w)`)= 9.81kN/m
`^(3)`

γ
`_(d)` = 2.75 × 1000/(1 + 0.95) = 13.83kN/m
`^(3)`